pendulum
Period of a pendulum:
2*pi*sqrt(L/g)
for 7m, this is 5.3s, or 2.66s/tick.
A 30-tooth last wheel: 159s/rotation
A weight descending from a 30cm-diameter drum (.94m circumference)
descends 7m/day. 7m/86400s
1day = 7.4 rotations.
7.4 rot / 86400 s =
8.56 e-5 rot/sec.
11676 sec/rot = 3.24h/rot
reduction needed 11676/159 = 73.4x
in 2 steps: 73.4 = 9 x 8.16
in 3 steps: 73.4 = 4.18 x 4.18 x 4.18
-----------------------------------------
2.66s/tick - 23 teeth -> 61.8 sec
20 teeth & 60 sec = 3s/tooth
8.94m would give one tick per 3.00 s
7.51m 2.75 s
6.21m 2.50 s
2.61s/tick & 23 teeth x2 = 120s/revolution 6.76m 22.2'
2.50s/tick & 24 = 120 6.21m 20.4'
2.73 22 120 7.39m 24.3'
---------------------------------------
7m/24h ~ 29.17 cm/h
116.67 circ drum = 37.14 cm diameter -> .25 rev/hour, 6 rev/day
1 rev in 14400 sec
14400/120 = 120x reduction
120 = 6 x 5 x 4
120 = 12 x 10
Hubert van Hecke
Last modified: Tue Jun 27 16:38:42 MDT 2017